48000Hz x 16b x 2ch = 1536000 (bits)
(48000Hz x 16b x 2) / 8 = 192000 (Bytes) = 192 (KB)
192(KB) / 1024 = 0.1875(MB)
The device can capture 192 kilobytes of data per second.
Sampling rate: 48000 Hz, bit depth: 16-bit, channels: 2. How much audio data can the device capture within one second?
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